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(C) Total number of cards in a pack = $52$.Let $A$ be the event of drawing a king and $B$ be the event of drawing a diamond.Number of kings,$n(A) = 4$

Vedclass · Accepted Answer

$\frac{4}{13}$

Vedclass · Answer

(C) Total number of cards in a pack = $52$.Let $A$ be the event of drawing a king and $B$ be the event of drawing a diamond.Number of kings,$n(A) = 4$.Number of diamonds,$n(B) = 13$.Number of cards that are both a king and a diamond (king of diamonds),$n(A \cap B) = 1$.Using the addition theorem of probability,$P(A \cup B) = P(A) + P(B) - P(A \cap B)$.$P(A \cup B) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52}$.Simplifying the fraction,we get $\frac{16}{52} = \frac{4}{13}$.

One card is drawn from a pack of $52$ cards. The probability that it is a king or a diamond is

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