On treating $SO_2$ with an aqueous solution of $KMnO_4$,the manganese ion reduces to

  • A
    $Mn^{2+}$ only
  • B
    $Mn^{4+}$ only
  • C
    $Mn^{6+}$ only
  • D
    $Mn^{4+}$ and $Mn^{6+}$

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The unbalanced chemical reactions given in List-$I$ show missing reagent or condition $(?)$ which are provided in List-$II$. Match List-$I$ with List-$II$ and select the correct answer using the code given below the lists:
List-$I$ List-$II$
$P. \ PbO_2 + H_2SO_4 \xrightarrow{?} PbSO_4 + O_2 + \text{other product}$ $1. \ NO$
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