On the axis and on the equator of an electric | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electric potential $V$ due to an electric dipole at a point $(r, 	heta)$ is given by the formula:$V(r, 	heta) = \frac{1}{4 \pi \varepsilon_0

Vedclass · Accepted Answer

on the axis $V 
eq 0$ and on equator $V = 0$

Vedclass · Answer

(D) The electric potential $V$ due to an electric dipole at a point $(r, 	heta)$ is given by the formula:$V(r, 	heta) = \frac{1}{4 \pi \varepsilon_0} \frac{p \cos 	heta}{r^2}$$1$. On the axis of the dipole,the angle $	heta$ is either $0$ or $\pi$ radians. Substituting this into the formula:$V = \frac{1}{4 \pi \varepsilon_0} \frac{p \cos(0)}{r^2} = \frac{p}{4 \pi \varepsilon_0 r^2}$ or $V = \frac{1}{4 \pi \varepsilon_0} \frac{p \cos(\pi)}{r^2} = -\frac{p}{4 \pi \varepsilon_0 r^2}$Thus,on the axis,$V 
eq 0$.$2$. On the equatorial plane of the dipole,the angle $	heta = \frac{\pi}{2}$ radians. Substituting this into the formula:$V = \frac{1}{4 \pi \varepsilon_0} \frac{p \cos(\pi/2)}{r^2} = 0$ (since $\cos(\pi/2) = 0$)Thus,on the equator,$V = 0$.Therefore,the correct option is $D$.

On the axis and on the equator of an electric dipole for all points . . . . . . .

Similar Questions

The ratio of the electric field on the axial line to the equatorial line of a short electric dipole is:

The distance between the two charges $+q$ and $-q$ of a dipole is $r$. On the axial line at a distance $d$ from the centre of the dipole,the electric field intensity is proportional to:

Three charges $+2q$,$+3q$,and $-4q$ are situated at $(0, -3a)$,$(2a, 0)$,and $(-2a, 0)$ respectively in the $xy$ plane. The resultant dipole moment about the origin is . . . . . .

The angle between the electric field and the dipole moment at any point on the equatorial plane of an electric dipole is . . . . . . . (in $^{\circ}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module