On moving a charge of 20 ; C by 2 ; cm,2 ; J | vedclass

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Question

(C) The work done $W$ in moving a charge $Q$ between two points with a potential difference $\Delta V$ is given by the formula:$W = Q \cdot \Delta V$G

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(C) The work done $W$ in moving a charge $Q$ between two points with a potential difference $\Delta V$ is given by the formula:$W = Q \cdot \Delta V$Given:Charge $Q = 20 \; C$Work done $W = 2 \; J$We need to find the potential difference $\Delta V$.Rearranging the formula for $\Delta V$:$\Delta V = \frac{W}{Q}$Substituting the given values:$\Delta V = \frac{2 \; J}{20 \; C} = 0.1 \; V$Therefore,the potential difference between the points is $0.1 \; V$.

On moving a charge of $20 \; C$ by $2 \; cm$,$2 \; J$ of work is done. The potential difference between the points is (in $V$):

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