On comparing the ratios frac{a_{1}}{a_{2}}, f | vedclass

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(B) Given equations are:$6x - 3y + 10 = 0$$2x - y + 9 = 0$Comparing these equations with the standard form $a_{1}x + b_{1}y + c_{1} = 0$ and $a_{2}x +

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(B) Given equations are:$6x - 3y + 10 = 0$$2x - y + 9 = 0$Comparing these equations with the standard form $a_{1}x + b_{1}y + c_{1} = 0$ and $a_{2}x + b_{2}y + c_{2} = 0$,we get:$a_{1} = 6, b_{1} = -3, c_{1} = 10$$a_{2} = 2, b_{2} = -1, c_{2} = 9$Now,calculating the ratios:$\frac{a_{1}}{a_{2}} = \frac{6}{2} = \frac{3}{1} = 3$$\frac{b_{1}}{b_{2}} = \frac{-3}{-1} = \frac{3}{1} = 3$$\frac{c_{1}}{c_{2}} = \frac{10}{9}$Since $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} 
eq \frac{c_{1}}{c_{2}}$,the lines representing the given pair of equations are parallel to each other. Therefore,these lines will never intersect at any point,and there is no solution for the given pair of equations.

On comparing the ratios $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}}$ and $\frac{c_{1}}{c_{2}},$ find out whether the lines representing the following pairs of linear equations intersect at a point,are parallel or coincident:
$6x - 3y + 10 = 0$
$2x - y + 9 = 0$

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On comparing the ratios $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}}$ and $\frac{c_{1}}{c_{2}},$ find out whether the lines representing the following pairs of linear equations intersect at a point,are parallel or coincident:$6x - 3y + 10 = 0$$2x - y + 9 = 0$