Observe the following reactions:I. 2H_2O_{(l) | vedclass

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(C) In reaction $I$,the oxidation state of $H$ in $H_2O$ changes from $+1$ to $0$ (in $H_2$),which is a decrease in oxidation number,hence water is re

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In reaction $I$ water is reduced and in reaction $II$ water is oxidized.

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(C) In reaction $I$,the oxidation state of $H$ in $H_2O$ changes from $+1$ to $0$ (in $H_2$),which is a decrease in oxidation number,hence water is reduced.In reaction $II$,the oxidation state of $O$ in $H_2O$ changes from $-2$ to $0$ (in $O_2$),which is an increase in oxidation number,hence water is oxidized.Therefore,in reaction $I$ water is reduced and in reaction $II$ water is oxidized.

Observe the following reactions:
$I$. $2H_2O_{(l)} + 2Na_{(s)} \rightarrow 2NaOH_{(aq)} + H_{2(g)}$
$II$. $2H_2O_{(l)} + 2F_{2(g)} \rightarrow 4H^{+}_{(aq)} + 4F^{-}_{(aq)} + O_{2(g)}$
Identify the correct statement from the following:

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Observe the following reactions:$I$. $2H_2O_{(l)} + 2Na_{(s)} \rightarrow 2NaOH_{(aq)} + H_{2(g)}$$II$. $2H_2O_{(l)} + 2F_{2(g)} \rightarrow 4H^{+}_{(aq)} + 4F^{-}_{(aq)} + O_{2(g)}$Identify the correct statement from the following: