Number of optical isomers of lactic acid are

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(b) $C{H_3} - \mathop {\mathop {\mathop {\mathop {{C^*}}\limits_{|\,\,\,\,} }\limits_{OH} }\limits^{|\,\,\,\,} }\limits^{H\,\,}  - COOH$

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$2$

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(b) $C{H_3} - \mathop {\mathop {\mathop {\mathop {{C^*}}\limits_{|\,\,\,\,} }\limits_{OH} }\limits^{|\,\,\,\,} }\limits^{H\,\,}  - COOH$

Only one chiral centre. Hence two optical isomers are possible.

No. of optical isomer = ${2^n}$ (where n = no. of chiral carbon) = ${2^1}$ $= 2.$

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