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(B) The structure of butan-$2,3$-diol is $CH_3-CH(OH)-CH(OH)-CH_3$.It has two chiral centers $(n=2)$.Since the molecule is symmetrical,the number of o

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$2$

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(B) The structure of butan-$2,3$-diol is $CH_3-CH(OH)-CH(OH)-CH_3$.It has two chiral centers $(n=2)$.Since the molecule is symmetrical,the number of optically active stereoisomers is given by $2^{n-1}$.Here,$n=2$,so the number of optically active isomers $= 2^{2-1} = 2^{1} = 2$.These two optically active isomers are the $(2R, 3R)$ and $(2S, 3S)$ forms. The $(2R, 3S)$ form is a meso compound and is optically inactive.

How many optically active stereoisomers are possible for butan-$2,3$-diol?

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