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(B) The reaction sequence involves the conversion of an alcohol $(X)$ to an azide with inversion of configuration at the chiral center.$1$) Treatment

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(B) The reaction sequence involves the conversion of an alcohol $(X)$ to an azide with inversion of configuration at the chiral center.$1$) Treatment of the alcohol with $PBr_3$ in $Et_2O$ converts the $-OH$ group into a $-Br$ group with inversion of configuration (via $S_N2$ mechanism).$2$) Treatment with $NaI$ in $Me_2CO$ (Finkelstein reaction) converts the $-Br$ group into a $-I$ group with further inversion of configuration.$3$) Treatment with $NaN_3$ in $HCONMe_2$ $(DMF)$ performs an $S_N2$ substitution of the iodide with the azide ion $(-N_3)$,resulting in a third inversion of configuration.Since there are three successive $S_N2$ inversions,the final product has the same relative configuration as the starting material $X$.The final product shown is a cyclopentane ring with a methyl group (wedge) and an azide group (dash). Since the starting material $X$ must have the same configuration as the product,$X$ must have the methyl group (wedge) and the hydroxyl group (wedge). This corresponds to structure $(B)$.

In the following reaction sequence,the correct structure$(s)$ of $X$ is (are)
$X$ $\xrightarrow[2) NaI, Me_2CO]{1) PBr_3, Et_2O}$ $\xrightarrow{3) NaN_3, HCONMe_2} \text{enantiomerically pure product}$

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In the following reaction sequence,the correct structure$(s)$ of $X$ is (are)$X$ $\xrightarrow[2) NaI, Me_2CO]{1) PBr_3, Et_2O}$ $\xrightarrow{3) NaN_3, HCONMe_2} \text{enantiomerically pure product}$