Number of electrons flowing per second in a conductor carrying a current of $9 \,A$ is

  • A
    $3 \times 10^{19}$
  • B
    $5.6 \times 10^{19}$
  • C
    $5.6 \times 10^{20}$
  • D
    $3 \times 10^{20}$

Explore More

Similar Questions

$A$ current of $4.8\,A$ is flowing through a conductor. The number of electrons flowing per second is:

The electric current flowing through a given conductor varies with time as shown in the graph below. The number of free electrons which flow through a given cross-section of the conductor in the time interval $0 \leq t \leq 20 \ s$ is

If a current of $1.6 \, mA$ is flowing in a conducting wire,then the number of electrons flowing per second is:

In an electrolyte,$3.2 \times 10^{18}$ bivalent positive ions drift to the right per second,while $3.6 \times 10^{18}$ monovalent negative ions drift to the left per second. Then the current is:

Current passing through a wire as a function of time is given as $I(t) = 0.02t + 0.01 \ A$. The charge that will flow through the wire from $t = 1 \ s$ to $t = 2 \ s$ is: (in $C$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo