If a current of 1.6 , mA is flowing in a cond | vedclass

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(B) The formula for electric current is $I = \frac{q}{t} = \frac{ne}{t}$,where $I$ is the current,$n$ is the number of electrons,$e$ is the elementary

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$10^{16}$

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(B) The formula for electric current is $I = \frac{q}{t} = \frac{ne}{t}$,where $I$ is the current,$n$ is the number of electrons,$e$ is the elementary charge,and $t$ is the time.Given: $I = 1.6 \, mA = 1.6 	imes 10^{-3} \, A$,$t = 1 \, s$,and $e = 1.6 	imes 10^{-19} \, C$.Rearranging the formula to solve for $n$: $n = \frac{I 	imes t}{e}$.Substituting the values: $n = \frac{1.6 	imes 10^{-3} 	imes 1}{1.6 	imes 10^{-19}}$.$n = 10^{-3} 	imes 10^{19} = 10^{16}$.Therefore,the number of electrons flowing per second is $10^{16}$.

If a current of $1.6 \, mA$ is flowing in a conducting wire,then the number of electrons flowing per second is:

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