Nuclear binding energy is equivalent to

If $M_0$ is the mass of isotope ${ }_{5}^{12} B$,$M_p$ and $M_n$ are the masses of a proton and a neutron respectively,then the nuclear binding energy of the isotope is:

The mass of a nucleus $_Z^AX$ is denoted by $M(A, Z)$. If $M_p$ and $M_n$ are the masses of a proton and a neutron respectively, the binding energy of this nucleus is given by:

The binding energy per nucleon of ${}_3^7Li$ and ${}_2^4He$ nuclei are $5.60\,MeV$ and $7.06\,MeV$ respectively. In the nuclear reaction ${}_3^7Li + {}_1^1H \to 2{}_2^4He + Q$, the value of energy $Q$ released is.........$MeV$.

The energy equivalent of $1 \text{ kg}$ of matter is about

The binding energy per nucleon of $^{209}_{83}Bi$ is . . . . . . MeV. [Take $m(^{209}_{83}Bi) = 208.980388 \text{ u}$,$m_p = 1.007825 \text{ u}$,$m_n = 1.008665 \text{ u}$,$1 \text{ u} = 931 \text{ MeV}/c^2$]