Nitrogen present in an unknown organic compou | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the correct compound,we calculate the percentage of nitrogen in each option using the formula: $	ext{Percentage of } N = \frac{	ext{Atom

Vedclass · Accepted Answer

pyridine

Vedclass · Answer

(B) To find the correct compound,we calculate the percentage of nitrogen in each option using the formula: $	ext{Percentage of } N = \frac{	ext{Atomic mass of } N}{	ext{Molar mass of compound}} 	imes 100$.$A$. Nitrobenzene $(C_6H_5NO_2)$: Molar mass = $123 \ g/mol$. $\%N = \frac{14}{123} 	imes 100 = 11.38 \%$.$B$. Pyridine $(C_5H_5N)$: Molar mass = $79 \ g/mol$. $\%N = \frac{14}{79} 	imes 100 = 17.72 \%$.$C$. Nitromethane $(CH_3NO_2)$: Molar mass = $61 \ g/mol$. $\%N = \frac{14}{61} 	imes 100 = 22.95 \%$.$D$. Aniline $(C_6H_7N)$: Molar mass = $93 \ g/mol$. $\%N = \frac{14}{93} 	imes 100 = 15.05 \%$.Comparing these values with the given $17.7 \%$,the compound is pyridine.

Nitrogen present in an unknown organic compound was estimated by the Dumas method to be $17.7 \%$ by weight. The compound is very likely to be ....

Similar Questions

Calculate the percentage of nitrogen in $0.25 \ g$ of an organic compound if $38 \ cm^3$ of $N_2$ gas is evolved at $300 \ K$ and $96 \ kPa$ pressure. (Given: $1 \ atm = 101.3 \ kPa$)

Which of the following substances cannot be analyzed using the Kjeldahl method for the estimation of nitrogen?

In the Carius method of estimation of halogen,$0.15 \ g$ of an organic compound gave $0.12 \ g$ of $AgBr$. Find out the percentage of bromine in the compound.

Which element is estimated by the Carius method?

In the Carius method for the estimation of halogen,$0.172 \ g$ of an organic compound showed the presence of $0.08 \ g$ of bromine. Which of these is the correct structure of the compound?

Vedclass Test Series

Exam Paper Generator

Online Exam Module