(D) Let the initial capacity of the container be $x$ litres of water.After the first operation,the amount of water left is $(x - 9)$ litres.After the

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(D) Let the initial capacity of the container be $x$ litres of water.After the first operation,the amount of water left is $(x - 9)$ litres.After the second operation,the amount of water left is $x(1 - 9/x)^2$ litres.The ratio of water to the total volume is $16 : (16 + 9) = 16 : 25$.Therefore,the fraction of water remaining is $\frac{x(1 - 9/x)^2}{x} = \frac{16}{25}$.$(1 - 9/x)^2 = (4/5)^2$.$1 - 9/x = 4/5$.$9/x = 1 - 4/5 = 1/5$.$x = 45$ litres.The container holds $45$ litres of liquid.

Competitive Quantitative Aptitude Mixture and Alligation Mixture and Alligation

Medium

Nine litres of water are drawn from a container full of water and it is then filled with milk. Nine litres of mixture are drawn and the container is again filled with milk. The ratio of the quantity of water now left in the container to that of the milk in it is $16:9$. How much liquid does the container hold? (in $litres$)

A
$34$
B
$38$
C
$43$
D
$45$

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Mixture and Alligation

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Mixture and Alligation

$A$ sum of $Rs. 41$ was divided among $50$ children. Each boy gets $90$ paise and each girl $65$ paise. The number of boys is?

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An alloy is made by mixing metal $A$ costing ₹ $2000/kg$ and metal $B$ costing ₹ $400/kg$ in the ratio $A:B = 3:1$. What is the cost (in ₹) of $8$ kilograms of this alloy?

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Gold is $19$ times as heavy as water and copper is $9$ times. In what ratio should these metals be mixed so that the mixture may be $15$ times as heavy as water?

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$100$ $litres$ of a mixture contains $20 \%$ water and the rest is milk. The amount of milk that must be added so that the resulting mixture contains $87.5 \%$ milk is (in $litres$):

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$A$ mixture of milk and water measures $60 \, ltr$. It contains $20 \%$ water. How many litres of water should be added to it so that water may be $25 \% $ (in $ltr$)?

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$A$ sum of $Rs. 41$ was divided among $50$ children. Each boy gets $90$ paise and each girl $65$ paise. The number of boys is?

An alloy is made by mixing metal $A$ costing ₹ $2000/kg$ and metal $B$ costing ₹ $400/kg$ in the ratio $A:B = 3:1$. What is the cost (in ₹) of $8$ kilograms of this alloy?

Gold is $19$ times as heavy as water and copper is $9$ times. In what ratio should these metals be mixed so that the mixture may be $15$ times as heavy as water?

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