Neutrino is a particle which
Neutrino is a particle which
- A
Has no charge and no spin
- B
Has no charge but has spin
- C
Is charged like an electron and has spin
- D
Has no charge but has mass nearly equal to that of a proton
Similar Questions
In an $\alpha -$ decay, the kinetic energy of $\alpha -$ particle is $48\, MeV$ and $Q$ value of the reaction is $50\, MeV$. The mass number of the mother nucleus is [assume that daughter nucleus is inground state]
In an $\alpha -$ decay, the kinetic energy of $\alpha -$ particle is $48\, MeV$ and $Q$ value of the reaction is $50\, MeV$. The mass number of the mother nucleus is [assume that daughter nucleus is inground state]
Explain the basic nuclear process by equation in $\beta -$ decay.
Explain the basic nuclear process by equation in $\beta -$ decay.
A nuclear decay is possible if the mass of the parent nucleus exceeds the total mass of the decay particles. If $M(A, Z)$ denotes the mass of a single neutral atom of an element with mass number $A$ and atomic number $Z$, then the minimal condition that the $\beta$ decay $X_Z^A \rightarrow Y_{Z+1}^A+\beta^{-}+\bar{v}_e$ will occur is ( $m_e$ denotes the mass of the $\beta$ particle and the neutrino mass $m_v$ can be neglected)
A nuclear decay is possible if the mass of the parent nucleus exceeds the total mass of the decay particles. If $M(A, Z)$ denotes the mass of a single neutral atom of an element with mass number $A$ and atomic number $Z$, then the minimal condition that the $\beta$ decay $X_Z^A \rightarrow Y_{Z+1}^A+\beta^{-}+\bar{v}_e$ will occur is ( $m_e$ denotes the mass of the $\beta$ particle and the neutrino mass $m_v$ can be neglected)
- [KVPY 2013]
Assertion: ${}_Z{X^A}$ undergoes a $2\alpha -$ decays, $2\beta -$ decays and $2\gamma - $ decays and the daughter product is ${}_{Z - 2}{X^{A - 8}}$
Reason : In $\alpha - $decays the mass number decreases by $4$ and atomic number decreases by $2$. In $2\beta - $ decays the mass number remains unchanged, but atomic number increases by $1$ only.
Assertion: ${}_Z{X^A}$ undergoes a $2\alpha -$ decays, $2\beta -$ decays and $2\gamma - $ decays and the daughter product is ${}_{Z - 2}{X^{A - 8}}$
Reason : In $\alpha - $decays the mass number decreases by $4$ and atomic number decreases by $2$. In $2\beta - $ decays the mass number remains unchanged, but atomic number increases by $1$ only.
- [AIIMS 2001]
A nucleus $X$ undergoes following transformation
$X \stackrel{a}{\longrightarrow} Y$
$Y \underset{2 \beta}{\longrightarrow} Z$
then
A nucleus $X$ undergoes following transformation
$X \stackrel{a}{\longrightarrow} Y$
$Y \underset{2 \beta}{\longrightarrow} Z$
then