Name the elements of the earth's magnetic field.
(N/A) The earth's magnetic field at any point on the surface is completely specified by three physical quantities, which are known as the elements of the earth's magnetic field:
$1$. Magnetic Declination $(\theta)$: The angle between the geographic meridian and the magnetic meridian at a place.
$2$. Magnetic Inclination or Angle of Dip $(\delta)$: The angle made by the total magnetic field vector of the earth with the horizontal direction in the magnetic meridian.
$3$. Horizontal Component of the Earth's Magnetic Field $(B_H)$: The component of the earth's total magnetic field vector along the horizontal direction in the magnetic meridian.
$1$. Magnetic Declination $(\theta)$: The angle between the geographic meridian and the magnetic meridian at a place.
$2$. Magnetic Inclination or Angle of Dip $(\delta)$: The angle made by the total magnetic field vector of the earth with the horizontal direction in the magnetic meridian.
$3$. Horizontal Component of the Earth's Magnetic Field $(B_H)$: The component of the earth's total magnetic field vector along the horizontal direction in the magnetic meridian.
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Assume the dipole model for Earth's magnetic field $B$,which is given by:
$B_v = \text{vertical component of magnetic field} = \frac{\mu_0}{4\pi} \frac{2m \cos \theta}{r^3}$
$B_H = \text{horizontal component of magnetic field} = \frac{\mu_0}{4\pi} \frac{m \sin \theta}{r^3}$
where $\theta = 90^{\circ} - \text{latitude}$ as measured from the magnetic equator.
$(a)$ Find the loci of points for which the dip angle is $\pm 45^{\circ}$.
$B_v = \text{vertical component of magnetic field} = \frac{\mu_0}{4\pi} \frac{2m \cos \theta}{r^3}$
$B_H = \text{horizontal component of magnetic field} = \frac{\mu_0}{4\pi} \frac{m \sin \theta}{r^3}$
where $\theta = 90^{\circ} - \text{latitude}$ as measured from the magnetic equator.
$(a)$ Find the loci of points for which the dip angle is $\pm 45^{\circ}$.
Medium
View SolutionThe angle of dip at a place is $30^{\circ}$,and the horizontal component of the Earth's magnetic field is $5 \times 10^{-5} \, T$. Calculate the vertical component and the total magnetic field at that place.
Medium
View SolutionThe angle of dip at a place is $40.6^\circ$ and the intensity of the vertical component of the earth's magnetic field $V = 6 \times 10^{-5} \text{ Tesla}$. The total intensity of the earth's magnetic field $(I)$ at this place is:
Medium
View SolutionAt a certain place,the vertical component of the Earth's magnetic field is $\sqrt{3}$ times the horizontal component of the Earth's magnetic field. If a magnetic needle is suspended freely in the air,then it will incline:
Medium
View SolutionFill in the blanks:
$(i)$ The declination is ...... at higher latitudes.
$(ii)$ The declination in India is ...... .
$(i)$ The declination is ...... at higher latitudes.
$(ii)$ The declination in India is ...... .
Medium
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