At a certain place,the vertical component of the Earth's magnetic field is $\sqrt{3}$ times the horizontal component of the Earth's magnetic field. If a magnetic needle is suspended freely in the air,then it will incline:
- A$30^{\circ}$ below horizontal
- B$60^{\circ}$ below horizontal
- C$30^{\circ}$ above horizontal
- D$45^{\circ}$ above horizontal
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Similar Questions
Consider the plane $S$ formed by the dipole axis and the axis of the Earth. Let $P$ be a point on the magnetic equator and in plane $S$. Let $Q$ be a point of intersection of the geographical and magnetic equators. Obtain the declination and dip angles at $P$ and $Q$.
Medium
View SolutionEarth's magnetic field always has a horizontal component except at,or the horizontal component of Earth's magnetic field remains zero at:
Easy
View SolutionIf ${\phi_1}$ and ${\phi_2}$ are the angles of dip observed in two vertical planes at right angles to each other and ${\phi}$ is the true angle of dip,then:
Difficult
View SolutionAssertion: If a compass needle is kept at the magnetic north pole of the Earth,the compass needle may stay in any direction.
Reason: $A$ dip needle will stay vertical at the north pole of the Earth.
Reason: $A$ dip needle will stay vertical at the north pole of the Earth.
At a point $A$ on the earth's surface, the angle of dip is $\delta = +25^{\circ}$. At a point $B$ on the earth's surface, the angle of dip is $\delta = -25^{\circ}$. We can interpret that:
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