Most stable carbocation is

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(C) The stability of carbocations is determined by factors such as resonance,hyperconjugation,and inductive effects. $A$: Cyclohexyl carbocation is a

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Cyclohexa$-2,4-$dien$-1-$yl carbocation

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(C) The stability of carbocations is determined by factors such as resonance,hyperconjugation,and inductive effects. $A$: Cyclohexyl carbocation is a secondary $(2^{\circ})$ alkyl carbocation with no resonance stabilization. $B$: Cyclohex$-2-$en$-1-$yl carbocation is an allylic carbocation,which is stabilized by resonance with the adjacent double bond. $C$: Cyclohexa$-2,4-$dien$-1-$yl carbocation is a conjugated dienyl carbocation. It has more resonance structures compared to the allylic carbocation in $B$,making it more stable due to extended delocalization of the positive charge. $D$: Phenyl carbocation is an $sp$-hybridized carbocation where the positive charge is on the ring,which is highly unstable due to the high electronegativity of the $sp$-hybridized carbon. Comparing these,the resonance stabilization in the conjugated system of $C$ makes it the most stable among the given options.

Similar Questions

What is the correct order of stability for $1^\circ, 2^\circ, 3^\circ$ carbocations and benzyl carbocation?

The correct order of the relative stability of the following carbanions is:
$I$. $HC \equiv C^{-}$
$II$. $CH_2=CH-CH_2^{-}$
$III$. $H_2C=CH^{-}$
$IV$. $(C_6H_5)_2CH^{-}$

For the following carbocations,the correct order of stability is:
$I: ^+CH_2-COCH_3$
$II: ^+CH_2-OCH_3$
$III: ^+CH_2-CH_3$

What is the correct order of stability for free radicals?

The bond dissociation energy of the $C-H$ bond for the compounds: $(I)\ CH_3-H, (II)\ CH_3-CH_2-H, (III)\ CH_2=CH-CH_2-H, (IV)\ C_6H_5-H$ follows the order:

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