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(D) The stability of carbocations is determined by electronic effects:$1$. In $II$ $(^+CH_2-OCH_3)$,the oxygen atom has lone pairs that can donate ele

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$I < III < II$

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(D) The stability of carbocations is determined by electronic effects:$1$. In $II$ $(^+CH_2-OCH_3)$,the oxygen atom has lone pairs that can donate electron density through resonance ($+M$ effect),completing the octet of the carbon atom,making it the most stable.$2$. In $III$ $(^+CH_2-CH_3)$,the ethyl group provides stability through hyperconjugation and the inductive effect ($+I$ effect) of the methyl group.$3$. In $I$ $(^+CH_2-COCH_3)$,the carbonyl group $(-C=O)$ is a strong electron-withdrawing group ($-I$ and $-M$ effect),which destabilizes the positive charge,making it the least stable.Therefore,the order of stability is $I < III < II$.

Label	Carbocation
$1$	$CH_3-CH^+-CH_3$
$2$	$CH_3^+$
$3$	$(CH_3)_3C^+$
$4$	$CH_3-CH_2^+$

For the following carbocations,the correct order of stability is:
$I: ^+CH_2-COCH_3$
$II: ^+CH_2-OCH_3$
$III: ^+CH_2-CH_3$

Similar Questions

Consider the following statements. Of these statements:
$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$
$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$

Which free radical from the following is least stable?

Which of the following represents the incorrect stability order?

Arrange the following carbocations in the increasing order of stability with respect to their labels:
Label Carbocation
$1$ $CH_3-CH^+-CH_3$
$2$ $CH_3^+$
$3$ $(CH_3)_3C^+$
$4$ $CH_3-CH_2^+$

Which of the following carbocations will undergo rearrangement?

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For the following carbocations,the correct order of stability is:$I: ^+CH_2-COCH_3$$II: ^+CH_2-OCH_3$$III: ^+CH_2-CH_3$