(A) Moseley's law states that the square root of the frequency of characteristic $X$-rays is directly proportional to the atomic number $(Z)$ of the t

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(A) Moseley's law states that the square root of the frequency of characteristic $X$-rays is directly proportional to the atomic number $(Z)$ of the target element.Mathematically,this is expressed as $\sqrt{f} = a(Z - b)$,where $a$ and $b$ are constants.Squaring both sides,we get $f = a^2(Z - b)^2$.Since $a^2$ is also a constant,the law is represented as $f = a(Z - b)^2$.

Class 12 Physics Atoms X-Rays

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Moseley measured the frequency $(f)$ of the characteristic $X$-rays from many metals of different atomic number $(Z)$ and represented his results by a relation known as Moseley's law. This law is ($a, b$ are constants)

A
$f = a(Z - b)^2$
B
$Z = a(f - b)^2$
C
$f^2 = a(Z - b)$
D
$f = a(Z - b)^{1/2}$

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Moseley measured the frequency $(f)$ of the characteristic $X$-rays from many metals of different atomic number $(Z)$ and represented his results by a relation known as Moseley's law. This law is ($a, b$ are constants)

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In an $X$-ray tube,the wavelength of characteristic $X$-rays is a property of .......

If $10000\, V$ is applied across an $X$-ray tube,what will be the ratio of the de-Broglie wavelength of the incident electrons to the shortest wavelength of $X$-rays produced? (Given: $\frac{e}{m}$ for an electron is $1.8 \times 10^{11}\, C\, kg^{-1}$)

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