Molecular weight of an organic acid is given by
- AEquivalent weight $\times$ basicity
- B$\frac{\text{Equivalent weight}}{\text{Basicity}}$
- C$\frac{\text{Basicity}}{\text{Equivalent weight}}$
- DEquivalent weight $\times$ valency
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Assertion : The normality of $0.3 \ M$ aqueous solution of $H_3PO_3$ is equal to $0.6 \ N$.
Reason : Equivalent weight of $H_3PO_3 = \frac{\text{Molecular weight of } H_3PO_3}{3}$
Reason : Equivalent weight of $H_3PO_3 = \frac{\text{Molecular weight of } H_3PO_3}{3}$
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