Chlorine exists in two isotopic forms ^{35}Cl | vedclass

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(B) Let the percentage abundance of $^{35}Cl$ be $x$ and that of $^{37}Cl$ be $(100 - x)$.Average atomic mass is given by the formula:$	ext{Average a

Vedclass · Accepted Answer

$75 \%, 25 \%$

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(B) Let the percentage abundance of $^{35}Cl$ be $x$ and that of $^{37}Cl$ be $(100 - x)$.Average atomic mass is given by the formula:$	ext{Average atomic mass} = \frac{(	ext{mass of } ^{35}Cl 	imes x) + (	ext{mass of } ^{37}Cl 	imes (100 - x))}{100}$Substituting the values:$35.5 = \frac{35x + 37(100 - x)}{100}$$3550 = 35x + 3700 - 37x$$3550 = 3700 - 2x$$2x = 3700 - 3550$$2x = 150$$x = 75$Therefore,the abundance of $^{35}Cl$ is $75 \%$ and the abundance of $^{37}Cl$ is $100 - 75 = 25 \%$.

Chlorine exists in two isotopic forms $^{35}Cl$ and $^{37}Cl$. If the average atomic mass of chlorine is $35.5$,what is the percentage abundance of these isotopes respectively?

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