The molecular shapes of XeF_3^+ and SNF_3 spe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For $XeF_3^+$: The central atom $Xe$ has $8$ valence electrons. $XeF_3^+$ has $8 - 3 + 1 = 6$ electrons,which corresponds to $3$ bond pairs and $2

Vedclass · Accepted Answer

$T$-shaped,Tetrahedral

Vedclass · Answer

(A) For $XeF_3^+$: The central atom $Xe$ has $8$ valence electrons. $XeF_3^+$ has $8 - 3 + 1 = 6$ electrons,which corresponds to $3$ bond pairs and $2$ lone pairs. The steric number is $5$,indicating $sp^3d$ hybridization. With $2$ lone pairs in the equatorial positions,the shape is $T$-shaped.For $SNF_3$: The central atom $S$ is bonded to $N$ (triple bond) and $3$ $F$ atoms (single bonds). The total number of electron pairs around $S$ is $4$ ($1$ triple bond + $3$ single bonds). The steric number is $4$,indicating $sp^3$ hybridization. The geometry is tetrahedral.

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

The molecular shapes of $XeF_3^+$ and $SNF_3$ species are respectively:

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

Choose the correct answer from the options given below:

Which of the following pairs of compounds consists of an equal number of lone pairs of electrons in the valence shell of the central atom?

Which of the following molecules is linear?

Which one of the following compounds has a bond angle of nearly $90^{\circ}$?

Identify the number of molecules in which the central atom has one lone pair of electrons from the following list:
$PbCl_2, PH_3, ClF_3, SF_4, BF_3, SnCl_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module