Which of the following molecules is linear?

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(A) To determine the shape of the molecules,we look at their hybridization and $VSEPR$ theory: $1$. $BeCl_2$: Beryllium has $2$ valence electrons. It

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$BeCl_2$

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(A) To determine the shape of the molecules,we look at their hybridization and $VSEPR$ theory: $1$. $BeCl_2$: Beryllium has $2$ valence electrons. It forms two bonds with Chlorine atoms. The hybridization is $sp$,resulting in a linear geometry with a bond angle of $180^{\circ}$. $2$. $H_2O$: Oxygen has $6$ valence electrons. It forms two bonds with Hydrogen and has two lone pairs. The hybridization is $sp^3$,resulting in a bent or $V$-shape. $3$. $SO_2$: Sulfur has $6$ valence electrons. It forms two double bonds with Oxygen and has one lone pair. The hybridization is $sp^2$,resulting in a bent shape. $4$. $CH_4$: Carbon has $4$ valence electrons. It forms four bonds with Hydrogen. The hybridization is $sp^3$,resulting in a tetrahedral geometry. Therefore,$BeCl_2$ is the linear molecule.

List-$I$	List-$II$
$I$. $XeF_4$	$A$. See-saw
$II$. $I_3^-$	$B$. Tetrahedral
$III$. $XeO_2F_2$	$C$. Bond angle $90^o$
$IV$. $SO_4^{2-}$	$D$. Linear

Similar Questions

The correct increasing order of adjacent bond angle among $BF_3$,$PF_3$,and $ClF_3$ is:

The number of molecules/ions having a trigonal bipyramidal shape is $........$.
$PF_5, BrF_5, PCl_5, [PtCl_4]^{2-}, BF_3, Fe(CO)_5$

Explain why $PCl_5$ is trigonal bipyramidal whereas $IF_5$ is square pyramidal.

Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists.

List-$I$ List-$II$

$I$. $XeF_4$ $A$. See-saw

$II$. $I_3^-$ $B$. Tetrahedral

$III$. $XeO_2F_2$ $C$. Bond angle $90^o$

$IV$. $SO_4^{2-}$ $D$. Linear

In which of the following is the bond angle maximum?

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