Mean of 50 observations was found to be 80.4. | vedclass

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(D) Given that the mean of $50$ observations is $80.4$.$	ext{Sum of observations} = 	ext{Mean} 	imes 	ext{Number of observations} = 80.4 	imes 50

Vedclass · Accepted Answer

$80.94$

Vedclass · Answer

(D) Given that the mean of $50$ observations is $80.4$.$	ext{Sum of observations} = 	ext{Mean} 	imes 	ext{Number of observations} = 80.4 	imes 50 = 4020$.It was discovered that $96$ was misread as $69$. To find the correct sum,we subtract the incorrect value and add the correct value:$	ext{Correct sum} = 4020 - 69 + 96 = 4047$.Now,calculate the correct mean:$	ext{Correct mean} = \frac{	ext{Correct sum}}{	ext{Number of observations}} = \frac{4047}{50} = 80.94$.

Class interval	$5-10$	$10-15$	$15-25$	$25-45$	$45-75$
Frequency	$6$	$12$	$10$	$8$	$15$

Mean of $50$ observations was found to be $80.4$. But later on,it was discovered that $96$ was misread as $69$ at one place. Find the correct mean.

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