The maximum usable frequency (MUF) in the F-r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for the maximum usable frequency $(MUF)$ is given by $MUF = \frac{f_c}{\cos 	heta}$,where $f_c$ is the critical frequency and $	heta

Vedclass · Accepted Answer

$175$

Vedclass · Answer

(C) The formula for the maximum usable frequency $(MUF)$ is given by $MUF = \frac{f_c}{\cos 	heta}$,where $f_c$ is the critical frequency and $	heta$ is the angle of incidence.Given: $f_c = 60 \, MHz$ and $	heta = 70^\circ$.Substituting the values: $MUF = \frac{60}{\cos 70^\circ}$.Since $\cos 70^\circ \approx 0.342$,we have $MUF = \frac{60}{0.342} \approx 175.43 \, MHz$.Rounding to the nearest integer,we get $x = 175 \, MHz$.

The maximum usable frequency $(MUF)$ in the $F$-region layer is $x$,when the critical frequency is $60 \, MHz$ and the angle of incidence is $70^\circ$. Then $x$ is ....... $MHz$.

Similar Questions

What are the primary causes of signal attenuation in an optical fiber?

If the height of the transmitting tower is increased by $30 \%$,then the area covered by it increases by (in $\%$)

$A$ carrier wave of peak voltage $60 \,V$ is used to transmit a message signal. Then the peak voltage of the modulating signal in order to have a modulation index of $90 \%$ is (in $\,V$)

When the angle of incidence is $74^{\circ}$,the critical frequency of the $F$ layer is $50 \text{ MHz}$. What is the Maximum Usable Frequency $(MUF)$ in $\text{ MHz}$ (in $.5$)?

What type of modulation is employed in India for radio transmission?

Vedclass Test Series

Exam Paper Generator

Online Exam Module