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(C) The $5^{th}$ excited state corresponds to the principal quantum number $n = 6$ (since ground state is $n = 1$).For a sample containing only one hy

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$5$

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(C) The $5^{th}$ excited state corresponds to the principal quantum number $n = 6$ (since ground state is $n = 1$).For a sample containing only one hydrogen atom,the electron can only undergo transitions from $n = 6$ to $n = 1$ in a single path,but the question asks for the maximum number of spectral lines possible for a single atom transitioning from $n = 6$ to $n = 1$.However,in a single atom,the electron can only occupy one energy level at a time and can only emit one photon per transition. If the electron transitions from $n = 6$ to $n = 1$ in a single atom,the maximum number of spectral lines it can emit is equal to the number of steps it takes to reach the ground state,which is $n - 1 = 6 - 1 = 5$ lines.Thus,the maximum number of spectral lines for a single atom is $n - 1 = 5$.

List-$I$	List-$II$
$(1)$ Lyman	$(A)$ $n = 5 \to n = 4$
$(2)$ Paschen	$(B)$ $n = 3 \to n = 2$
$(3)$ Brackett	$(C)$ $n = 6 \to n = 5$
$(4)$ Balmer	$(D)$ $n = 4 \to n = 3$
	$(E)$ $n = 7 \to n = 6$

Maximum number of spectral lines possible when an electron jumps from $5^{th}$ excited state to ground state in a sample containing only one Hydrogen atom will be

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