Match the reagents in List-I with the product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reactions of phenol are as follows:$a$. Phenol reacts with $(i)$ $NaOH$,$(ii)$ $CO_2$,$(iii)$ $H^{+}$ to form Salicylic acid (Kolbe's reaction

Vedclass · Accepted Answer

$a-iv, b-iii, c-ii, d-i$

Vedclass · Answer

(C) The reactions of phenol are as follows:$a$. Phenol reacts with $(i)$ $NaOH$,$(ii)$ $CO_2$,$(iii)$ $H^{+}$ to form Salicylic acid (Kolbe's reaction). Thus,$a-iv$.$b$. Phenol reacts with $(i)$ Aqueous $NaOH + CHCl_3$,$(ii)$ $H^{+}$ to form Salicylaldehyde (Reimer-Tiemann reaction). Thus,$b-iii$.$c$. Phenol reacts with $Zn$ dust upon heating to form Benzene. Thus,$c-ii$.$d$. Phenol reacts with $Na_2Cr_2O_7$ and $H_2SO_4$ (chromic acid) to form Benzoquinone. Thus,$d-i$.Therefore,the correct matching is $a-iv, b-iii, c-ii, d-i$.

List-$I$	List-$II$
$a$. $(i)$ $NaOH$,$(ii)$ $CO_2$,$(iii)$ $H^{+}$	$i$. Benzoquinone
$b$. $(i)$ Aqueous $NaOH + CHCl_3$,$(ii)$ $H^{+}$	$ii$. Benzene
$c$. $Zn$ dust,$\Delta$	$iii$. Salicylaldehyde
$d$. $Na_2Cr_2O_7, H_2SO_4$	$iv$. Salicylic acid

Similar Questions

Reaction of phenol with which of the following reagents forms picric acid?

Identify $A$ in the following reaction: $A + \text{Acetic anhydride} \xrightarrow{H^{+}} \text{Aspirin} + \text{Acetic acid}$

In the given reaction: $[X] +$ Acetic anhydride $\rightarrow$ Aspirin,$[X]$ will be:

The major product in the given reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module