Match the following: List-I (Compound)List-II | vedclass

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(A) The acidity of compounds depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $p-$Nitrophenol $(A)$: The

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$A-I, B-II, C-III, D-IV$

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(A) The acidity of compounds depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $p-$Nitrophenol $(A)$: The nitro group $(-NO_2)$ is a strong electron-withdrawing group ($-I$ and $-M$ effect),which stabilizes the phenoxide ion significantly,making it the most acidic. Its $pK_a$ is $7.1$ $(I)$.$2$. Phenol $(B)$: Phenol is more acidic than ethanol but less acidic than $p-$nitrophenol. Its $pK_a$ is $10.0$ $(II)$.$3$. Ethanol $(C)$: Aliphatic alcohols are much less acidic than phenols due to the electron-donating alkyl group ($+I$ effect) which destabilizes the alkoxide ion. Its $pK_a$ is $15.9$ $(III)$.$4$. $p-$Cresol $(D)$: The methyl group $(-CH_3)$ is an electron-donating group ($+I$ and hyperconjugation),which destabilizes the phenoxide ion compared to phenol,making it less acidic. Its $pK_a$ is $10.2$ $(IV)$.Therefore,the correct matching is $A-I, B-II, C-III, D-IV$.

List-$I$ (Compound)	List-$II$ $(pK_a)$
$A$. $p-$Nitrophenol	$I$. $7.1$
$B$. Phenol	$II$. $10.0$
$C$. Ethanol	$III$. $15.9$
$D$. $p-$Cresol	$IV$. $10.2$

Match the following:
List-$I$ (Compound) List-$II$ $(pK_a)$
$A$. $p-$Nitrophenol $I$. $7.1$
$B$. Phenol $II$. $10.0$
$C$. Ethanol $III$. $15.9$
$D$. $p-$Cresol $IV$. $10.2$
The correct answer is

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Match the following: List-$I$ (Compound)List-$II$ $(pK_a)$$A$. $p-$Nitrophenol$I$. $7.1$$B$. Phenol$II$. $10.0$$C$. Ethanol$III$. $15.9$$D$. $p-$Cresol$IV$. $10.2$ The correct answer is