Match the following columns.
colum $I$
colum $II$
$(A)$ Constant positive acceleration
$(p)$ Speed may increase
$(B)$ Constant negative acceleration
$(q)$ Speed may decrease
$(C)$ Constant displacement
$(r)$ Speed is zero
$(D)$ Constant slope of $a-t$ graph
$(s)$ Speed must increase
| colum $I$ | colum $II$ |
| $(A)$ Constant positive acceleration | $(p)$ Speed may increase |
| $(B)$ Constant negative acceleration | $(q)$ Speed may decrease |
| $(C)$ Constant displacement | $(r)$ Speed is zero |
| $(D)$ Constant slope of $a-t$ graph | $(s)$ Speed must increase |
- A$( A \rightarrow p , q , B \rightarrow p , q , C \rightarrow r , D \rightarrow p , q )$
- B$( A \rightarrow q , B \rightarrow p , C \rightarrow r , D \rightarrow p , q )$
- C$( A \rightarrow p , r , B \rightarrow p , s , C \rightarrow r , D \rightarrow p , q )$
- D$( A \rightarrow p , q , B \rightarrow p , q , C \rightarrow r , D \rightarrow p , q )$
Similar Questions
A person sitting in a moving train with his face towards the engine, throws a coin vertically upwards. The coin falls ahead of person. The train:
A person sitting in a moving train with his face towards the engine, throws a coin vertically upwards. The coin falls ahead of person. The train:
A ball is dropped and its displacement versus time graph is as shown (Displacement $x$ from ground and all quantities are positive upwards).
$(a)$ Plot qualitatively velocity versus time graph.
$(b)$ Plot qualitatively acceleration versus time graph.
A ball is dropped and its displacement versus time graph is as shown (Displacement $x$ from ground and all quantities are positive upwards).
$(a)$ Plot qualitatively velocity versus time graph.
$(b)$ Plot qualitatively acceleration versus time graph.
Refer to the graph in figure. Match the following
Acceleration-time graph of a body is shown. The corresponding velocity-time graph of the same body is
Acceleration-time graph of a body is shown. The corresponding velocity-time graph of the same body is
The relation between time ' $t$ ' and distance ' $x$ ' is $t=$ $\alpha x^2+\beta x$, where $\alpha$ and $\beta$ are constants. The relation between acceleration $(a)$ and velocity $(v)$ is:
The relation between time ' $t$ ' and distance ' $x$ ' is $t=$ $\alpha x^2+\beta x$, where $\alpha$ and $\beta$ are constants. The relation between acceleration $(a)$ and velocity $(v)$ is:
- [JEE MAIN 2024]