Match List-$I$ with List-$II$.
List-$I$ (Functional group detection)List-$II$ (Change observed during detection)
$A$. Unsaturation (Baeyer's test)$I$. Red colour appears
$B$. Alcoholic group (Ceric ammonium nitrate test)$II$. Silver mirror appears
$C$. Aldehyde group (Tollen's reagent)$III$. Violet colour appears
$D$. Phenolic group ($FeCl_3$ test)$IV$. Discharge of pink colour

Choose the correct answer from the options given below:

  • A
    $A-III, B-IV, C-II, D-I$
  • B
    $A-III, B-IV, C-I, D-II$
  • C
    $A-IV, B-III, C-II, D-I$
  • D
    $A-IV, B-III, C-I, D-II$

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Similar Questions

Match List-$I$ with List-$II$.
List-$I$ Element detected List-$II$ Reagent used/Product formed
$A$. Nitrogen $I$. $Na_2[Fe(CN)_5NO]$
$B$. Sulphur $II$. $AgNO_3$
$C$. Phosphorus $III$. $Fe_4[Fe(CN)_6]_3$
$D$. Halogen $IV$. $(NH_4)_2MoO_4$

Choose the correct answer from the options given below:

Which one of the following reactions does $NOT$ belong to "Lassaigne's test"?

If $N$ and $S$ are present in an organic compound during the Lassaigne test,then both change into:

Difficult
View Solution

The sodium fusion extract is boiled with concentrated nitric acid while testing for halogens. By doing so,it

Given below are two statements :
Statement $I :$ In Lassaigne's test,the covalent organic molecules are transformed into ionic compounds.
Statement $II :$ The sodium fusion extract of an organic compound having $N$ and $S$ gives prussian blue colour with $FeSO_4$ and $FeCl_3$.
In the light of the above statements,choose the correct answer from the options given below.

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