Match List-I (Event) with List-II (Order of t | vedclass

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(A) The rotation period of the Earth is approximately $24$ hours, which is $24 	imes 3600 \approx 8.64 	imes 10^4 \, s \approx 10^5 \, s$.The revolu

Vedclass · Accepted Answer

$(1)-(i), (2)-(ii), (3)-(iii), (4)-(iv)$

Vedclass · Answer

(A) The rotation period of the Earth is approximately $24$ hours, which is $24 	imes 3600 \approx 8.64 	imes 10^4 \, s \approx 10^5 \, s$.The revolution period of the Earth is $1$ year, which is $365 	imes 24 	imes 3600 \approx 3.15 	imes 10^7 \, s \approx 10^7 \, s$.The period of a light wave is calculated using $T = \frac{\lambda}{c}$. For visible light, $\lambda \approx 5000 \, \mathring{A} = 5 	imes 10^{-7} \, m$ and $c = 3 	imes 10^8 \, m/s$. Thus, $T \approx \frac{5 	imes 10^{-7}}{3 	imes 10^8} \approx 1.6 	imes 10^{-15} \, s \approx 10^{-15} \, s$.The period of a sound wave (audible range) is typically in the range of $10^{-3} \, s$ (e.g., for $1 \, kHz$, $T = 10^{-3} \, s$).Matching these: $(1)-(i), (2)-(ii), (3)-(iii), (4)-(iv)$.

List-$I$	List-$II$
$(1)$ Rotation period of earth	$(i)$ $10^5\, s$
$(2)$ Revolution period of earth	$(ii)$ $10^7\, s$
$(3)$ Period of light wave	$(iii)$ $10^{-15}\, s$
$(4)$ Period of sound wave	$(iv)$ $10^{-3}\, s$

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