Identify the correctly matched set from the f | vedclass

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(A) $1$. For $[NiCl_4]^{2-}$,$Ni$ is in the $+2$ oxidation state ($3d^8$ configuration). $Cl^-$ is a weak field ligand,so it does not cause pairing. I

Vedclass · Accepted Answer

$[NiCl_4]^{2-}$ - Tetrahedral - Paramagnetic

Vedclass · Answer

(A) $1$. For $[NiCl_4]^{2-}$,$Ni$ is in the $+2$ oxidation state ($3d^8$ configuration). $Cl^-$ is a weak field ligand,so it does not cause pairing. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry with $2$ unpaired electrons,making it paramagnetic. Thus,option $A$ is correct.$2$. For $[Ni(CO)_4]$,$Ni$ is in the $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry with $0$ unpaired electrons,making it diamagnetic.$3$. For $[Ni(CN)_4]^{2-}$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing. It undergoes $dsp^2$ hybridization,resulting in a square planar geometry with $0$ unpaired electrons,making it diamagnetic.

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Similar Questions

Which of the following matches is incorrect?
Complex compounds $-$ Type of hybridization

According to the valence bond theory,the hybridization of the central metal atom is $dsp^{2}$ for which one of the following compounds?

What is the number of $d$-electrons in the metal ion of the tetrahedral complex $K_2[NiCl_4]$?

If $Ni^{2+}$ is replaced by $Pt^{2+}$ in the complex $[NiCl_2Br_2]^{2-}$,which of the following properties are expected to change?
$A.$ Geometry
$B.$ Geometrical isomerism
$C.$ Optical isomerism
$D.$ Magnetic properties

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