Masses of three wires of copper are in the ratio of $1 : 3 : 5$ and their lengths are in the ratio of $5 : 3 : 1$. The ratio of their electrical resistances is

  • A
    $1 : 3 : 5$
  • B
    $5 : 3 : 1$
  • C
    $1 : 15 : 125$
  • D
    $125 : 15 : 1$

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