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(A) The reaction involves the protonation of the tertiary alcohol group containing the $^{18}O$ isotope. Upon protonation,the $^{18}OH_2^+$ group acts

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(A) The reaction involves the protonation of the tertiary alcohol group containing the $^{18}O$ isotope. Upon protonation,the $^{18}OH_2^+$ group acts as a good leaving group,leading to the formation of a tertiary carbocation. The neighboring primary alcohol group then acts as a nucleophile,attacking the carbocation to form a cyclic ether. Since the $^{18}O$ atom is lost as water,the oxygen atom in the resulting cyclic ether is the one from the primary alcohol group,not the $^{18}O$ isotope. Therefore,the major product is the cyclic ether formed by the intramolecular nucleophilic attack,where the $^{18}O$ is excluded from the ring.

The major product obtained in the reaction is:

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