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(C) $1)$ The amino group of aniline is acetylated with $CH_3COCl$ / pyridine to form acetanilide $(P)$.$2)$ It is then brominated with $Br_2$ / $CH_3C

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p-bromoaniline

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(C) $1)$ The amino group of aniline is acetylated with $CH_3COCl$ / pyridine to form acetanilide $(P)$.$2)$ It is then brominated with $Br_2$ / $CH_3COOH$. Since the $-NHCOCH_3$ group is ortho/para directing (due to the lone pair on $N$ activating the ring),bromine enters the para position,making the para product the major one $(Q)$.$3)$ The final step is acid hydrolysis,where the $-NHCOCH_3$ group is hydrolysed back to the $-NH_2$ group.Thus,the final product $R$ is $p$-bromoaniline.

The major product $(R)$ of the following reaction is:
Aniline $\xrightarrow[{pyridine}]{{CH_3COCl}}$ $P$ $\xrightarrow[{CH_3COOH}]{{Br_2}}$ $Q$ $\xrightarrow{{{H_3O^{+}}}}$ $R$

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The major product $(R)$ of the following reaction is:Aniline $\xrightarrow[{pyridine}]{{CH_3COCl}}$ $P$ $\xrightarrow[{CH_3COOH}]{{Br_2}}$ $Q$ $\xrightarrow{{{H_3O^{+}}}}$ $R$