Major product 'P' formed in the following rea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction involves the electrophilic addition of $Br_2$ to the alkene group of pent$-4-$enoic acid. $1$. $Br_2$ reacts with the double bond to

Vedclass · Accepted Answer

Vedclass · Answer

(B) The reaction involves the electrophilic addition of $Br_2$ to the alkene group of pent$-4-$enoic acid. $1$. $Br_2$ reacts with the double bond to form a cyclic bromonium ion intermediate. $2$. The base $NaHCO_3$ deprotonates the carboxylic acid group to form a carboxylate anion $(R-COO^-)$. $3$. This carboxylate anion acts as an internal nucleophile and attacks the more substituted carbon of the bromonium ion,leading to an intramolecular cyclization (halolactonization). $4$. This results in the formation of a five-membered lactone ring with a bromomethyl group attached,which is the major product $P$.

Major product '$P$' formed in the following reaction is:-

Similar Questions

The major product of the following reaction is $CH_3-CH(Br)-CH_2-CH_3 + \text{alc. } KOH \to $

Identify the product of ozonolysis of $but-2-ene$ from the following:

The correct statement about the reaction shown above is:

The major product of the following reaction is $CH_3 - CH = CH_2 + HBr \xrightarrow{(C_6H_5CO)_2O_2}$

The major products of the following reaction are :

Vedclass Test Series

Exam Paper Generator

Online Exam Module