The major products of the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction proceeds in two steps:$1$. Dehydrohalogenation (or elimination of the leaving group) using $KO^tBu$ (a bulky base) and $\Delta$ (heat

Vedclass · Accepted Answer

$(CH_3)_2C=O + CH_3COOH$

Vedclass · Answer

(D) The reaction proceeds in two steps:$1$. Dehydrohalogenation (or elimination of the leaving group) using $KO^tBu$ (a bulky base) and $\Delta$ (heat) follows the $E2$ mechanism to form the most stable alkene (Hofmann product is not favored here as the substrate allows for the formation of the more substituted alkene).Starting material: $CH_3-CH(CH_3)-CH(OSO_2CH_3)-CH_3$.Elimination of $OSO_2CH_3$ and a proton from the adjacent carbon leads to the formation of $CH_3-CH(CH_3)-CH=CH_2$ ($3$-methylbut$-1-$ene) or $CH_3-CH(CH_3)-CH=CH-CH_3$ ($2$-methylbut$-2-$ene). The more substituted alkene,$CH_3-C(CH_3)=CH-CH_3$ ($2$-methylbut$-2-$ene),is the major product.$2$. Ozonolysis $(O_3/H_2O_2)$ of $CH_3-C(CH_3)=CH-CH_3$ leads to oxidative cleavage.$CH_3-C(CH_3)=CH-CH_3 \xrightarrow{O_3/H_2O_2} (CH_3)_2C=O + CH_3COOH$.Thus,the major products are acetone and acetic acid.

The major products of the following reaction are :

Similar Questions

The conversion shown below can be brought about by?

Which one of the following is an electrophilic addition reaction?

The reaction of $HBr$ with the following compound would produce:

The product$(s)$ in the following sequence of reactions will be: $Me-C \equiv C-Me \xrightarrow[2. \text{dil. alkaline } KMnO_4]{1. Na/NH_3(liq.), \text{ethanol}, -33^\circ C}$ Product$(s)$

How can ethene be produced from ethanol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module