Magnifying power of a simple microscope is (w | vedclass

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(B) For a simple microscope,the magnifying power $M$ is defined as the ratio of the angle subtended by the image at the eye to the angle subtended by

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$1 + D/f$

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(B) For a simple microscope,the magnifying power $M$ is defined as the ratio of the angle subtended by the image at the eye to the angle subtended by the object at the near point.When the final image is formed at the near point $D = 25 \ cm$,we use the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$.Here,$v = -D$ and $u = -u$. Substituting these values,we get: $\frac{1}{-D} - \frac{1}{-u} = \frac{1}{f}$.Rearranging the terms: $\frac{1}{u} = \frac{1}{f} + \frac{1}{D}$.Multiplying both sides by $D$,we get: $\frac{D}{u} = \frac{D}{f} + 1$.Since the magnifying power $M = \frac{D}{u}$,we have $M = 1 + \frac{D}{f}$.

Magnifying power of a simple microscope is (when final image is formed at $D = 25 \ cm$ from eye)

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