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(D) For coherent sources,the intensity at the central maximum is given by $I_{0} = (\sqrt{I_{1}} + \sqrt{I_{2}})^2$. Since both sources have the same

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$\frac{I_{0}}{2}$

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(D) For coherent sources,the intensity at the central maximum is given by $I_{0} = (\sqrt{I_{1}} + \sqrt{I_{2}})^2$. Since both sources have the same amplitude $A$,their individual intensities are equal,say $I_{1} = I_{2} = I$. Thus,$I_{0} = (\sqrt{I} + \sqrt{I})^2 = (2\sqrt{I})^2 = 4I$. This implies that the intensity of each individual source is $I = \frac{I_{0}}{4}$. When the sources are incoherent,the interference term averages to zero over time. Therefore,the resultant intensity is simply the sum of the individual intensities: $I_{res} = I_{1} + I_{2} = I + I = 2I$. Substituting $I = \frac{I_{0}}{4}$ into the expression,we get $I_{res} = 2 	imes (\frac{I_{0}}{4}) = \frac{I_{0}}{2}$.

Light from two coherent sources of the same amplitude $A$ and wavelength $\lambda$ illuminates the screen. The intensity of the central maximum is $I_{0}$. If the sources were incoherent,the intensity at the same point will be

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