Let the set of all values of $k \in R$ such that the equation $z(\bar{z} + 2 + i) + k(2 + 3i) = 0, z \in C$,has at least one solution,be the interval $[\alpha, \beta]$. Then $9(\alpha + \beta)$ is equal to:

  • A
    -$10$
  • B
    -$8$
  • C
    $10\sqrt{13}$
  • D
    $8\sqrt{13}$

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