Let the foot of the perpendicular from the point $(1, 2, 4)$ on the line $\frac{x+2}{4} = \frac{y-1}{2} = \frac{z+1}{3}$ be $P$. Then the distance of $P$ from the plane $3x + 4y + 12z + 23 = 0$ is:

  • A
    $5$
  • B
    $\frac{50}{13}$
  • C
    $4$
  • D
    $\frac{63}{13}$

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