Let $0 < P(A) < 1$,$0 < P(B) < 1$ and $P(A \cup B) = P(A) + P(B) - P(A)P(B).$ Then

  • A
    $P(A/B) = P(A)$
  • B
    $P(A^c \cup B^c) = P(A^c) + P(B^c)$
  • C
    $P((A \cup B)^c) = P(A^c)P(B^c)$
  • D
    $A$ and $C$ both

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