Let $f(x) = \begin{cases} \frac{\sin \pi x}{5x}, & x \ne 0 \\ k, & x = 0 \end{cases}$. If $f(x)$ is continuous at $x = 0$,then $k =$

  • A
    $\frac{\pi}{5}$
  • B
    $\frac{5}{\pi}$
  • C
    $1$
  • D
    $0$

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