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(A) Given functions are $f(x) = 5 - x^2$ and $g(x) = 3x - 4$. To find $(f \circ g)(-1)$,we use the definition of composition of functions: $(f \circ g

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-$44$

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(A) Given functions are $f(x) = 5 - x^2$ and $g(x) = 3x - 4$. To find $(f \circ g)(-1)$,we use the definition of composition of functions: $(f \circ g)(x) = f(g(x))$. First,calculate $g(-1)$: $g(-1) = 3(-1) - 4 = -3 - 4 = -7$. Now,substitute this value into $f(x)$: $(f \circ g)(-1) = f(g(-1)) = f(-7)$. Using the definition of $f(x)$: $f(-7) = 5 - (-7)^2 = 5 - 49 = -44$. Thus,the value of $(f \circ g)(-1)$ is $-44$.

Let $R$ be the set of real numbers and the mapping $f: R \rightarrow R$ and $g: R \rightarrow R$ be defined by $f(x) = 5 - x^2$ and $g(x) = 3x - 4$,then the value of $(f \circ g)(-1)$ is

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