Let $a > b > 0$ and $f(n) = a^{1/n} - b^{1/n}$,$J(n) = (a - b)^{1/n}$ for all $n \geq 2$. Then:

  • A
    $f(n) < J(n)$
  • B
    $f(n) > J(n)$
  • C
    $f(n) = J(n)$
  • D
    $f(n) + J(n) = 0$

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