Let S_1 be the amount of Rayleigh scattered l | vedclass

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(A) The condition for Rayleigh scattering is that the wavelength of the incident light must be much larger than the size of the scattering particle,i.

Vedclass · Accepted Answer

$\frac{S_1}{S_2}=\left(\frac{\lambda_2}{\lambda_1}\right)^4$,if $\lambda_1, \lambda_2 > a$

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(A) The condition for Rayleigh scattering is that the wavelength of the incident light must be much larger than the size of the scattering particle,i.e.,$\lambda \gg a$.According to Rayleigh's law of scattering,the intensity (or amount) of scattered light $S$ is inversely proportional to the fourth power of its wavelength $\lambda$,which is expressed as $S \propto \frac{1}{\lambda^4}$.Therefore,for two different wavelengths $\lambda_1$ and $\lambda_2$,the ratio of the scattered light amounts is given by $\frac{S_1}{S_2} = \frac{1/\lambda_1^4}{1/\lambda_2^4} = \left(\frac{\lambda_2}{\lambda_1}\right)^4$.This relationship holds true under the condition $\lambda_1, \lambda_2 \gg a$.

Let $S_1$ be the amount of Rayleigh scattered light of wavelength $\lambda_1$ and $S_2$ that of light of wavelength $\lambda_2$ from a particle of size $a$. Which of the following statements is true?

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