Let $X$ and $Y$ be two events of a sample space such that $P(X)=\frac{1}{3}$,$P(X|Y)=\frac{1}{2}$ and $P(Y|X)=\frac{2}{5}$,then which of the following is true?

  • A
    $P(X \cap Y)=\frac{1}{5}$
  • B
    $P(X \cup Y)=\frac{2}{5}$
  • C
    $P(Y)=\frac{4}{15}$
  • D
    $P(X \cup Y)=\frac{1}{2}$

Explore More

Similar Questions

Given $P(A)=0.5, P(B)=0.4, P(A \cap B)=0.3$,then $P(A^{\prime} / B^{\prime})$ is equal to

$A$ box contains $3$ white and $2$ red balls. $A$ ball is drawn and another ball is drawn without replacing the first ball. What is the probability that the second ball is red?

Difficult
View Solution

If two events $A$ and $B$ are such that $P(A^c) = 0.3$,$P(B) = 0.4$ and $P(A \cap B^c) = 0.5$,then $P(B | A \cup B^c)$ is equal to

If two unbiased dice are rolled simultaneously until a sum of the numbers appearing on these dice is either $7$ or $11$,then the probability that $7$ comes before $11$ is:

If two dice are rolled,then the probability of getting a multiple of $3$ as the sum of the numbers appeared on the top faces of the dice,given that their sum is an odd number,is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo