Let $a = \hat{i} - 2\hat{j} + 3\hat{k}$ and $b = 2\hat{i} + \hat{j} + \hat{k}$. If $c$ is a unit vector such that $[a \ b \ c]$ is maximum,then $c =$

  • A
    $\frac{-\hat{i} + \hat{j} + \hat{k}}{\sqrt{3}}$
  • B
    $\frac{2\hat{i} - \hat{j} - \hat{k}}{\sqrt{6}}$
  • C
    $\frac{2\hat{i} - \hat{j} + 3\hat{k}}{\sqrt{14}}$
  • D
    $\frac{\hat{i} + \hat{j} - 2\hat{k}}{\sqrt{6}}$

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