Let $A$ be the area of the in-circle and $A_1, A_2, A_3$ be the areas of the ex-circles of a triangle. If $A_1=4, A_2=9, A_3=16$,then $A=$

  • A
    $81$
  • B
    $\frac{61}{169}$
  • C
    $\frac{144}{61}$
  • D
    $\frac{144}{169}$

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